Expected Learning Outcomes
You are expected to:
- Recognize the sides of a right-angled triangle in different situations
- Identify the Pythagorean relationship in different situations
- Apply the Pythagorean relationship to real-life situations
- Promote the use of Pythagoras’ Theorem in real-life situations
Pythagorean Relationship – Grade 7 Mathematics
3.0 Measurements
3.1 Pythagorean Relationship
About 2000 years ago, an amazing discovery was made about right-angled triangles. If squares of length equivalent to the sides of the triangle are drawn, then the sum of the area of the two small squares is exactly the same as the area of the large square.
The Pythagoras theorem states that a2 + b2 = c2, where a and b are the shorter sides while c is the longest side. The longest side is known as the hypotenuse.
Example 3.1
Solve for the value of x in the triangle shown below.
From Pythagoras theorem 52 + 122 = x2
25 + 144 = x2
169 = x2
We now take square root both sides x = 13
Example 3.2
Find out which of the two triangles drawn below is right angled.
We start by testing (a)
Is (82 + 402) equal to 412
82 + 402 = 64 + 1600 = 1664
412 = 1681
From the calculation, (82 + 402) is not equal to 412
We therefore conclude that triangle (a) is not a right-angled triangle.
Then we test (b)
Is (392 + 522) equal to 652
392 + 522 = 1521 + 2704 = 4225
652 = 4225
We therefore conclude that triangle (b) is a right-angled triangle.
Example 3.3
A frame is made from a wire in the shape of a trapezium as shown below. Calculate the length of the wire used.
We let the side that is not given be x.
The length of wire will be (9 + 8 + 15 + x) cm.
To find the length x, we deduce a right-angled triangle from the diagram.
x2 = 62 + 82
x2 = 36 + 64
x2 = 100
x = 10
The length of the wire is therefore 9 cm + 8 cm + 15 cm + 10 cm = 42 cm.
Build the Right Triangle
Adjust the values of a and b. Observe how the areas change and test the Pythagorean Relationship.
3
4
a² = 9
b² = 16
c² = 25
Exercise 3.1
Solve the following questions using the Pythagorean Relationship.
Question 1
(a) x = cm
(b) x = cm
(c) x = cm
(a) √(13² − 12²) = √25 = 5
(b) √(10² − 6²) = √64 = 8
(c) √(25² − 24²) = √49 = 7
Question 2
Determine which triangles are right-angled.
(a)
(b)
(a) 48² + 64² = 6400 = 80² → right-angled
(b) 28² + 58² = 4356 ≠ 66² → Not Right-angled
Question 3
A 3.9 m ladder is placed against a wall. The foot of the ladder is 1.5 m from the wall. How far up the wall does the ladder reach?
Answer: m
Height² = 3.9² − 1.5²
= 15.21 − 2.25
= 12.96
Height = √12.96 = 3.6 m
Question 4
A rectangle is 20 cm long and 15 cm wide. Find the length of the diagonal.
Diagonal = cm
Diagonal² = 20² + 15²
= 400 + 225 = 625
Diagonal = √625 = 25 cm
Question 5
An airplane flies 480 km East and then 140 km North. How far is Wajir from Nairobi directly?
Distance = km
Distance² = 480² + 140²
= 230400 + 19600
= 250000
Distance = √250000 = 500 km
Question 6
AB = cm
From triangle BCD:
√(26² − 24²) = √100 = 10
From triangle ABC:
AB = √(10² - 6²) = √64 = 8 cm